**Practice Exam 2--Answers**

You can find answers to odd-numbered problems from the text in the text. Here are the answers to all other problems.

2) We complete the square in terms of x and in terms of y:

That gives us

.

Hence, the radius is r=5, the center is (-2,3).

3) (a) even (b) neither (c) odd (d) neither

8) (a) The discriminant =25+24=49. Hence, the equation has two real distinct solutions. They are =1, .

(b) The discriminant = 4-12=-8. Hence, the equation has two complex conjugate roots. Using the quadratic formula we obtain

, .

We can simplify them: and .

9) . Since the equation has roots , , we can factor

.

11) (b) None. .

12) For example, .

14) # 42:
*(x)= *
.

16) Graph of the inverse is symmetric with respect to the line y=x. Hence, the graph of the inverse, in blue is